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Mathematics

2 answers:

BlackZzzverrR [31]2 years ago

6 0

Median=11
Lower quartile=4
Upper quartile=16

Vadim26 [7]2 years ago

4 0

Answer: Answer:Median: 10.5Lower quartile: 4Upper quartile: 16Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 12 (even)Median = Mean of (6)th and (7)th observations = 10 + 11 divided by 2 = 21/2 = 10.5Therefore the median is 10.5.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 16Question 2.the lengths of 10 pencils, in centimeters:18, 15, 4, 9, 14, 17, 16, 6, 8, 10Type below:_________________Answer:Median: 12Lower quartile: 4Upper quartile: 18Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 10 (even)Median = Mean of (5)th and (6)th observations = 10 + 14 divided by 2 = 24/2 = 12Therefore the median is 12.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 18Question 3.Make a box plot to display the data set in Exercise 2.Type below:_________________Answer:The above box plot represents the lower and upper quartiles, the median.Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Question 4.The numbers of students on several teams are 9, 4, 5, 10, 11, 9, 8, and 6. Make a box plot for the data.Type below:_________________Answer: Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Therefore the lower and upper quartiles are 4 and 11 respectively.Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 8 (even)Median = Mean of (4)th and (5)th observations = 8 + 9 divided by 2 = 17/2 = 8.5Therefore the median is 8.5.

Step-by-step explanation:

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1. The prism-shaped roof has equilateral triangular bases. Create an equation that models the height of one of the roof's triang

Mandarinka [93]

1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is $\frac{ \sqrt{3} }{2} a$

2. if a a=25 ft, then the height is $\frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7$ (ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is $2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2}$

so the total area of the roof is $\frac{ \sqrt{3} }{2} a^{2} +3al$

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al

5. so the area now is $\frac{ \sqrt{3} }{2} a^{2} +2al$

6. now a=25 and l=2a=50

Area= $\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2} (\frac{ \sqrt{3} }{2} +4)=625*4.866$

=3041.3 (ft squared)