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Step2247 [10]
3 years ago
5

What type of covalent bond diagram only shows the outer shell of electrons?

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
Correct answer: <span>Dot-and-cross-diagram
</span>

Dot-and-cross diagrams are used to represent covalent bonds. The shared electron from one atom is shown as a dot, while the shared electron from the other atom is shown as a cross.

When drawing dot-and-cross diagrams for covalent bonds, you only need to show the electrons in the highest occupied energy level, as only these are involved.

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Angle RST is a right angle. Angle RSU has a measure of 25°.
Angelina_Jolie [31]

Keywords

complementary angles, right angle

we know that

If two angles are <u>complementary angles</u>, then their sum is equal to a <u>right angle</u>

In this problem

Angle\ RSU+Angle\ TSU=90\° -------> by <u>complementary angles</u>

we have

Angle\ RSU=25\°

Substitute and solve for Angle TSU

Angle\ TSU=90\°-25\°=65\°

therefore

the answer is the option

65\°

5 0
3 years ago
Read 2 more answers
Please help me i beg you!!! 30 points!!!
Westkost [7]
The third is because the prove is x = fifteen and if a number is next to a letter, it means multiply, sorry I could only do one.
6 0
3 years ago
Read 2 more answers
Brainly!
bezimeni [28]

Answer:

1/15

Step-by-step explanation:

There are a total of 10 fruits, 3 of which are apples.

The probability that the first selection is an apple is 3/10.

There are now 9 fruits remaining, 2 of which are apples.  So the probability that the second fruit is an apple is 2/9.

The total probability is (3/10) (2/9) = 1/15.

5 0
2 years ago
2. Which is equivalent to the calculator output 8.954 E - 15?
anyanavicka [17]

Answer: 8.954 x 10^-15

Step-by-step explanation:

i took a test with this question and this was the answer

8 0
2 years ago
Find the indicated probability. round to three decimal places. a test consists of 10
Charra [1.4K]

To answer this problem, we use the binomial distribution formula for probability:

P (x) = [n! / (n-x)! x!] p^x q^(n-x)

Where,

n = the total number of test questions = 10

<span>x = the total number of test questions to pass =   >6</span>

p = probability of success = 0.5

q = probability of failure = 0.5

Given the formula, let us calculate for the probabilities that the student will get at least 6 correct questions by guessing.

P (6) = [10! / (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10! / (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10! / (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10! / (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10! / (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

Total Probability = 0.376953 = 0.38 = 38%

<span>There is a 38% chance the student will pass.</span>

7 0
3 years ago
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