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3 years ago

5

What type of covalent bond diagram only shows the outer shell of electrons?

1 answer:

vitfil [10]3 years ago

4 0

Correct answer: <span>Dot-and-cross-diagram
</span>

Dot-and-cross diagrams are used to represent covalent bonds. The shared electron from one atom is shown as a dot, while the shared electron from the other atom is shown as a cross.

When drawing dot-and-cross diagrams for covalent bonds, you only need to show the electrons in the highest occupied energy level, as only these are involved.

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A bag of numbered lottery balls contains the numbers 1 through 40. What is the probability that a randomly selected ball will be

MA_775_DIABLO [31]

Answer:

3/40

Step-by-step explanation:

So we look for all the multiples of 13 not over 40

There are 3 which are; 13, 26, 39

So it will be 3/40

8 0

3 years ago

PQRS is a parallelogram with PQ=26cm and QR=20cm . If the distance between the longer-sides is 12.5cm , Find

Kay [80]

Answer:

Below.

Step-by-step explanation:

I am guessing you want the area of the parallelogram.

Take the longer side to be the base.

Area = base * distance between base and opposite side

= 26 * 12.5

= 325 cm^2.

6 0

2 years ago

Which of the following shows a group of possible angles a triangle could have?

Delvig [45]

Answer:

C. 60 degrees, 60 degrees, 60 degrees

Step-by-step explanation:

The measures of interior angles of a triangle sum to 180°.

8 0

3 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0

2 years ago

If A={g,y,m,n,a,s,t,i,c} and U={a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z}, find A′.

victus00 [196]

Is this a free point?

3 0

3 years ago