Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e









The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Answer:
Step-by-step explanation:
Let the two consecutive numbers be 2n and 2n+2
The sum of these numbers in 2n + (2n+2).
Hence
2n + (2n+2) = 34
4n + 2 = 34
4n = 32
n =8.
Answer:
-7 3/8
Step-by-step explanation:
The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

So our solution is -7 3/8
No because there is no picture and circles
Answer:
-3
Step-by-step explanation:
consider f(x)=y
y=-3x+7
compare with y=mx+c
slope m=-3