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liraira [26]
3 years ago
8

There are 400 people in a studio audience. The probability that a person chosen at random from this audience is male is 5/8. How

many males are in the audience?
Mathematics
1 answer:
leonid [27]3 years ago
4 0

Answer:

250 males

Step-by-step explanation:

So 8/8 is the whole which equals 400 in this problem. 4/8 would be 1/2 so it would equal 200. For this certain equation 400 divided into 8th's would be 50. So since there is 5/8 males then you do 5*50 which would equal 250.

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0
3 years ago
Please help I will mark Brainly
Sedbober [7]
The answer for your question is 686
8 0
2 years ago
Read 2 more answers
The perimeter of the rectangle below is 184 m .What is the value of y
stiks02 [169]

Step-by-step explanation:

2x + 2y = 184 ---- eqn 1

y = 184 - 2x / 2

y = 92 - x ---- eqn 2

7 0
3 years ago
How how is 1/2 + 1/4 solve differently than 1/2 + 1/3?
yulyashka [42]
1/2 + 1/4 =
2/4 + 1/4 =
3/4 <===
7 0
3 years ago
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The vertices of a triangle are p(3,7) Q(7,-6) R(-8,7). Name the vertices of the image reflected across the x axis
pantera1 [17]

Answer:

<em>P'(3,-7) Q'(7,6) R'(-8,-7).</em>

Step-by-step explanation:

<u>Reflection across the x-axis</u>

Given a point P(x,y), its reflection across the x-axis will map to point P'(x,-y), i.e., the y-coordinate gets inverted.

We are given the vertices of a triangle P(3,7) Q(7,-6) R(-8,7). The vertices of the image reflected across the x-axis are:

P'(3,-7) Q'(7,6) R'(-8,-7).

The new triangle has vertices P'Q'R'.

6 0
2 years ago
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