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SpyIntel [72]
3 years ago
13

The slopes of perpendicular lines are

Mathematics
1 answer:
Andrej [43]3 years ago
8 0

Answer:

B: Negative Reciprocals.

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Will give brainliest to correct answer
yanalaym [24]

Answer:

A or B or C or D, one of those

5 0
3 years ago
What is the range of this function(–11, 8) (13, 7) (14, 7)
scoray [572]

Answer:

The range is { 7,8}

Step-by-step explanation:

The range of the functions is the output values

We do not list the repeated values more than one and normally list them from smallest to largest

The range is { 7,8}

7 0
4 years ago
How do I divide whole numbers by fraction? (Ex: 12 ÷ 1⁄2)
Readme [11.4K]
That would be 6 just put the the whole number over one and keep flip change
7 0
3 years ago
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I need the answers please help 60points
enyata [817]
In 22, you're looking for the vertical height of the triangle. You're given the angle opposite the side you want to find (which I'll call x) and the length of the hypotenuse. This sets you up with the relation

\sin2^\circ=\dfrac x{1600}\implies x\approx55.84\text{ m}

In 23, you're given a similar situation, except now you're looking for the angle (I'll call it \theta) in the triangle opposite the side denoting the height of the airplane. So this time,

\sin\theta=\dfrac{1500}{5000}=\dfrac3{10}\implies\theta=\arcsin\dfrac3{10}\approx17.46^\circ
6 0
3 years ago
Read 2 more answers
6
8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16     Eqn 1

8x+5y=113    Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80    Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

\frac{3x}{3}=\frac{33}{3}\\x=11

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0
3 years ago
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