In order to solve this problem, we need to use the factor and remainder theorem. Suppose we have a quadratic equation of Q(x) and a binomial x-a=0, where a is a constant such that x=a. When you substitute x=a to the quadratic equation, you use the answer as basis. Whatever the answer is, is the remainder. If the answer is zero, that means that x=a is a factor.
In this case, we substitute x=3 to the quadratic equation and equate to zero to find k.
Q(x) = x²+kx-6
Q(3) = 3²+k(3)-6 = 0
k = -1
The value of k is -1.
Answer:
triangle abd is isosceles triangle and triangle dbc is equilateral triangle.
opposite sides of equal angles are same. so, ad= bd
and bd is the side of equilateral triangle. so, bd=bc=dc
perimeter of quadrilateral = sum of all sides.
perimeter=11+8+8+8
perimeter =35
Step-by-step explanation:
LHS=(1-sin60)/cos60
=(1-√3÷2)/1÷2
=2(1-√3÷2)
=2-√3
RHS=(1-tan30)/(1+tan30)
={1-(1÷√3)}/{1+(1÷√3)}
={(√3-1)/√3}/{(√3+1)/√3}
=(√3-1)/(√3+1)
={(√3-1)(√3-1)}/{(√3+1)(√3-1)}
=(3-√3-√3+1)/(3-1)
=(4-2√3)/2
=2-√3
Therefore LHS=RHS
Answer: -1,0
Step-by-step explanation:
I think because if you look at a grid and put your finger on -4,0 then go over 5 the back 3.
