HELP. WHAT'S THE CORRECT ANSWER?

Mary read a book that had 4200 pages last summer. If it took her 35 days to finish the book. How many pages did she read per day

kari74 [83]

120 Pages.....................

8 0

3 years ago

Mark is purchasing new tiles for his bathrooms. The home improvement store charges $48 for each box of tiles when three or fewer

shutvik [7]

Answer:

f(x)=

1. 48x when x < or = 3,

2. 45x when 4 < or = x < or = 8

3. 42x when 9 < or = x < or = 19

4. 38x when x > 19

Step-by-step explanation:

3 boxes or less = Cost of tiles = $48

4 - 8 boxes ; cost = $45

9 - 19 boxes ; cost = $42

> 19 boxes ; cost = $38

6 0

2 years ago

If the equation y=-5x+12 is translated up five units, what would the new equation be?

Maurinko [17]

Answer:

y=-5x+17

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

jesse had a balance of 1200 on a credit card with an APR of 18.7% compounded monthly. About how much will he save in interest ov

igor_vitrenko [27]

Jesse saved about $85.77 in interest over the course of a year if he transfer from one credit card to another.

<h3>What is the interest accrued on savings?</h3>

The interest accrued on saving is the interest gained on saving or investment over a period of time.

ar

The amount of money saved in interest by Jesse over a period of 12 months provided that the transferred his balance to a credit card is calculated as follows:

Amount saved = $\mathbf{P_x(1 + \dfrac{r}{P_x})^{12}-P_y(1 + \dfrac{r}{P_y})^{12}}$

Amount saved = $\mathbf{1200(1 + \dfrac{18.7}{1200})^{12} - 1200(1 + \dfrac{12.5}{1200})^{12}}$

Amount saved = $85.768

Amount saved = $85.77

Learn more about interest accrued on a savings here:

brainly.com/question/1434515

#SPJ1

5 0

2 years ago