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3 years ago

JWISOSOOS someone help me n show me how to do it 2. Thanks goodnight:>>

Mathematics

1 answer:

posledela3 years ago

4 0

Answer:

2/3(3x+9)=-2(2x+6)

2/3(3x+2x)=-2(9+6)

2/3×5x=-2+15

10x/3=13

3x=13

x=13-3

x=10

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Write the point-slope form of an equation of the line through the points (-7, 7) and (4, 1).

seraphim [82]

Answer:

Choice B. $\displaystyle y - 7 = -\frac{6}{11} \, (x + 7)$ .

Step-by-step explanation:

Start by finding the slope of this line. Let $(x_1,\, y_1)$ and $(x_2,\, y_2)$ represent two distinct points on a line on a Cartesian Plane. (That is, $x_1 \ne x_2$ .) The slope of this line would be:

$\displaystyle \frac{y_2 - y_1}{x_2 - x_1}$ .

For the line in this question:

$x_1 = -7$ ,
$y_1 = 7$ ;

$x_2 = 4,$
$y_2 = 1$ .

Indeed, $x_1 \ne x_2$ . The slope of this line would thus be $\displaystyle \frac{1 - 7}{4 - (-7)}$ , which is equal to $\displaystyle -\frac{6}{11}$ .

On a Cartesian Plane, the point-slope form of a line that has a slope of $m$ and includes the point $(x_0,\, y_0)$ can be written as:

$y - y_0 = m\, (x - x_0)$ .

(Note the minus signs in this form.)

For the line in this question, $m = \displaystyle -\frac{6}{11}$ . There are two equivalent expressions for its point-slope form:

Using the first point, $y - 7 = \displaystyle -\frac{6}{11}\, (x - (-7))$ . This equation is equivalent to $y - 7 = \displaystyle -\frac{6}{11}\, (x + 7)$ .
Using the second point, $y - 1 = \displaystyle -\frac{6}{11}\, (x - 4)$ .

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3 years ago

José borrowed a total of $72 from his grandmother. He borrowed $9 each week.

miskamm [114]

Answer:

Step-by-step explanation:8 x 9 = 72

8 0

3 years ago

Read 2 more answers

Lim 1 + cos TX<br>5.<br>x>1 tanưrex

Brums [2.3K]

Answer: 1/2

$\lim_{x \to 1}\frac{1+cos \pi x}{tan^{2}\pi x }\\\\ = \lim_{x \to 1} \frac{1+cos\pi x}{\frac{sin^{2}\pi x }{cos^{2}\pi x } } \\\\\\= \lim_{x \to 1}\frac{cos^{2}\pi x(1+cos\pi x) }{sin^{2}\pi x } \\\\\\= \lim_{x \to 1} \frac{cos^{2}\pi x(1+cos\pi x)}{1-cos^{2}\pi x } \\\\= \lim_{x \to 1} \frac{cos^{2}\pi x }{1-cos\pi x} \\\\= \lim_{x \to 1}\frac{cos^{2}\pi .1 }{1-cos\pi .1}\\\\= \lim_{x \to 1}\frac{1}{1-(-1)}\\\\=\frac{1}{2}$

Step-by-step explanation:

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2 years ago

Solve the equation 40a^2+4a=0

sergiy2304 [10]

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3 years ago

When using a quadratic equation of the form ax2 +bx+c=0 to find a distance what should be "ignored"

Aleksandr [31]

You should ignore the negative answers because you can't have negative distance. For example, if you are going back 7 feet, you are still going 7 feet. In that situation, the answer would 7 not -7.

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3 years ago