One number: x
Its consecutive: x + 1
Product:
x(x+1)=121
x² + x - 121 = 0
Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
Answer:
12.05%
Step-by-step explanation:
:D
Constants are numbers alone with no variables.
The constants are: 12, -3.7, 1/3
Sandra did not get enough points.
They needed 15, but got 22 and a -8 as well.
So 22-8 = 14
14<15
