Answer:
Once you know the volume of the displaced water, you can immediately determine its weight by multiplying by the density of water at the relevant temperature. That's because the definition of density (d) is mass (m) divided by volume (v), so m = dv.
Step-by-step explanation:
Answer:
- 150 short-sleeved shirts
- 100 long-sleeved shirts
Step-by-step explanation:
Let S and L represent the numbers of short- and long-sleeved shirts ordered.
The expected earnings were ...
5S +10L = 1750
The number sold was ...
(1/3)S + (1/2)L = 100
We can multiply the first equation by 1/5 and the second equation by 6 to put the equations into standard form:
Subtracting the second equation from twice the first gives ...
2(S +2L) -(2S +3L) = 2(350) -(600)
L = 100 . . . . . . simplify
2S +3(100) = 600
S = 150
150 short-sleeved and 100 long-sleeved shirts were ordered.
Answer:
3.0 Miles per hour
Step-by-step explanation:
https://www.countcalculate.com/cars-and-speed/average-speed/result?r=jfqffaktat
Substitute x for 7.
f(x)=22x+12
f(7)=22(7)+12
Multiply first, then complete addition.
f(7)=154+12
f(7)=166
Answer:
13 over 3
Step-by-step explanation:
Hi Jakeyriabryant! I hope you’re fine!
I hope I have understood the problem well.
If so, what the exercise raises is the following equality:
(x-1) / 5 = 2/3
From this equation you must clear the "x".
First, we pass the 5 that is dividing on the side of the x, to the other side and passes multiplying
(X – 1) / 5 = 2/3
(X – 1) = (2/3)*5
X – 1 = 10/3
Then we pass the one that is subtracting from the side of the x, to the other side and passes adding
X = 10/3 + 1
Remember that to add or subtract fractions they must have the same denominator or a common denominator (in this case we can write 1 as fraction 3/3). Then,
X = 10/3 + 3/3
X = 13/3
I hope I've been helpful!
Regards!
