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3 years ago

Which statements are true regarding the quadratic statement?

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

Answer:

Step-by-step explanation:

I hope am right coz it seems most appropriate

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How is do does I don’t know how do does

Akimi4 [234]

Huh? I’m not sure I understand what I just said...

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3 years ago

What is 15 1/8 - 1 3/5

AnnZ [28]

15 1/8 -1 3/5=
15 5/40 -1 24/40=
605/40 - 64/40=
541/40= 13 21/40

Answer:13 21/40

8 0

3 years ago

Read 2 more answers

Add. −38+(−2910) Enter your answer as a simplified fraction by filling in the boxes.

Bumek [7]

Answer:

-2948

Step-by-step explanation:

the only fraction it can be is -2948/1 but it is the same thing as the answer itself

4 0

2 years ago

Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12

umka2103 [35]

Answer:

The median = 5

The mode = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

The mode is the value which is repeated the most. = 7

Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

=7−(3*3) and 10+(3*3)

Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

6 0

3 years ago

Solve |p + 2| = 10Solve |p + 2| = 10 {-12} {-8, 8} {-12, 8}

valentinak56 [21]

By definition, we have

$|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}$

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that $p+2\geq 0 \iff p \geq -2$

In this case, the absolute value doesn't do anything: the equation is

$p+2 = 10 \iff p = 10-2 = 8$

We are supposing $p \geq -2$ , so we can accept this solution.

Now, suppose that $p+2 < 0 \iff p < -2$ . Now the sign of the expression is flipped by the absolute value, and the equation becomes

$-p-2 = 10 \iff -p = 12 \iff p = -12$

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0

3 years ago