<h3>
Answer: 15</h3>
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Work Shown:
d = common difference
p = first term = 24
q = second term = a+d = 24+d
r = third term = q+d = 24+d+d = 24+2d = 6
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Solve for d
24+2d = 6
2d = 6-24
2d = -18
d = -18/2
d = -9
We add -9 to each term to get the next term. This is the same as subtracting 9 from each term to get the next term.
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First term = 24
Second term = 24-9 = 15
Third term = 15-9 = 6
We get the sequence 24, 15, 6
Answer:
We must prove that (c+a)(c+d) = (b+c)(b+d)
- Let us use principles from mathematical induction
- a=bx , b=cx, c=dx
- a+c = b + c
- c +d = b + d
- Such that (a+c)(c+d)=(b+c)(b+d)
Rate positively and give brainlist
Combine like terms
-x = 4 + 6 - 3x
-x = 10 - 3x
Isolate the x, add 3x to both sides
-x (+3x) = 10 - 3x (+3x)
-x + 3x = 10
Simplify. Combine like terms
-x + 3x = 10
2x = 10
Isolate the x, divide 2 from both sides
2x/2 = 10/2
x = 10/2
x = 5
x = 5, or A is your answer
hope this helps
10 times 'x' is 10 times whatever the value of 'x' is. I hope that makes sense.
