Midpoint is the center point on the line segment <br> True or false?

A genetic test is used to determine if people have a predisposition for thrombosis, which is the formation of a blood clot insid

IceJOKER [234]

Idk mane but uh I just don’t know

4 0

3 years ago

Will give brainliest give the answer and steps

zvonat [6]

Answer:

m = (p+7n)/3

Step-by-step explanation:

3m-7n = p

3m = p+7n

m = (p+7n)/3

7 0

2 years ago

Lee wants to collect 22 of a certain type of action figure. He had 11 of the figures, then got 3 more for his birthday. What dec

Shalnov [3]

To solve this problem, we must first find the fraction of action figures that Lee has gotten so far. To do this, we will represent the number of action figures that Lee currently has in the numerator divided by the denominator, the total number of action figures that Lee is attempting to collect.

First, we must recognize that Lee currently has 11 action figures plus the 3 that he got for his birthday. To find the total number of action figures that Lee has, we must add together these two parts.

11+3 = 14

Therefore, Lee has 14 action figures (this will become the numerator of the fraction). The denominator of the fraction is the total number of action figures, which we are given is 22.

Thus, our fraction is 14/22.

To convert this into a decimal, we can simply divide the numerator of the fraction by the denominator of the fraction, which gives us:

14/22 = 0.636363636

Therefore, your answer is approximately 0.636.

Hope this helps!

6 0

3 years ago

Enter the explicit rule for the sequence

Softa [21]

Let's take a look at the first few numbers in the sequence based on the given rule:

$a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)$

Inspecting this pattern it seems like the power $\frac{1}{4}$ is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be $\big(\frac{1}{4} \big)^{n-1}$ . We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

$a_n=6\big( \frac{1}{4} \big)^{n-1}$

Where $a_n$ is the nth number in our sequence.