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likoan [24]
3 years ago
12

on Saturday morning Owen earned $29. By the end of the afternoon he had earned a total of $67. Enter an equation, using x as you

r variable to determine whether Owen earned $38 or $34 on Saturday afternoon
Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

$67 = $29 + $ x

Step-by-step explanation:

Given that on Saturday morning Owen earned= $29

End of afternoon amount total earned was= $67

Let's find the amount earned in the afternoon=?

Let's take the amount earned in the afternoon to be =$ x

Equation for total amount earned by the end of afternoon= $29 + $x

But we know total amount earned by end of afternoon was=$67 hence

the equation to determine afternoon amount will be;

$67 = $29 + $ x ----------------------------go ahead and solve for x

$67-$29 = $ x

$ 38 = x

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The battery on McKenzies old computer can last 4(1/5) hours. She bought a new computer that has a battery that can last 40% long
Solnce55 [7]

Answer:

5\frac{22}{25}\ hours

Step-by-step explanation:

we know that

4\frac{1}{5}\ hours=\frac{4*5+1}{5}=\frac{21}{5}\ hours

100\%+40\%=140\%=\frac{140}{100}

Let

x ------> new battery life

The equation that represent this situation is

x=\frac{140}{100} (\frac{21}{5})=\frac{2,940}{500}\ hours

convert to mixed number

\frac{2,940}{500}=\frac{2,500}{500}+\frac{440}{500}=5\frac{22}{25}\ hours

4 0
3 years ago
Multiply: –c2(3c – 2)
Naddik [55]

Answer:

3c^3+2c^2

Step-by-step explanation:

8 0
3 years ago
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What is the some need help????​
snow_tiger [21]

The sum formula for a geometric sequaence is:

sum(n) = a1(1-r^n)/1-r

Where n is the number of terms, a1 is the first term and r is the common ratio:

s(8) = 3(1-1/2^8) / (1-1/2)

s(8) = 3(1-1/256) / 1/2

s(8) = 2 253/256 / 1/2

s(8) = 765/128

The answer is C.

5 0
3 years ago
1.    An AP has a common difference of 3.  Given that the nth term is 32, and the sum of the first n terms is 185, calculate the
netineya [11]

Answer:

The value of n is 10

Step-by-step explanation:

The formula of the nth term of the arithmetic progression is a_{n} = a + (n - 1)d

  • a is the first term
  • d is the common difference between each 2 consecutive terms
  • n is the position of the term

The formula of the sum of nth terms is S_{n} = \frac{n}{2} [2a + (n - 1)d]

∵ An AP has a common difference of 3

∴ d = 3

∵ The nth term is 32

∴ a_{n} = 32

→ Substitute them in the 1st rule above

∵ 32 = a + (n - 1)3

∴ 32 = a + 3(n) - 3(1)

∴ 32 = a + 3n - 3

→ Add 3 to both sides

∴ 35 = a + 3n

→ Switch the two sides

∴ a + 3n = 35

→ Subtract 3n from both sides

∴ a = 35 - 3n ⇒ (1)

∵ The sum of the first n terms is 185

∴ S_{n} = 185

→ Substitute the value of S_{n} and d in the 2nd rule above

∵ 185 = \frac{n}{2} [ 2a + (n - 1)3]

∴ 185 = \frac{n}{2} [2a + 3(n) - 3(1)]

∴ 185 = \frac{n}{2} [2a + 3n - 3]

→ Multiply both sides by 2

∴ 370 = n(2a + 3n - 3)

∴ 370 = 2an + 3n² - 3n

→ Substitute a by equation (1)

∴ 370 = 2n(35 - 3n) + 3n² - 3n

∴ 370 = 70n - 6n²+ 3n² - 3n

→ Add the like terms in the right side

∵ 370 = -3n² + 67n

→ Add 3n² to both sides

∴ 3n² + 370 = 67n

→ Subtract 67 from both sides

∴ 3n² - 67n + 370 = 0

→ Use your calculator to find n

∴ n = 10 and n = 37/3

∵ n must be a positive integer ⇒ 37/3 neglecting

∴ n = 10

∴ The value of n is 10

4 0
3 years ago
What is 90times345 need it now
Ivanshal [37]
90*345=
31050
Hope i helped.
6 0
3 years ago
Read 2 more answers
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