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bulgar [2K]
3 years ago
12

What is the value of x? Enter your answer in the box. x = ° Triangle A B C. The measure of angle A is fifty five degrees, the me

asure of angle B is eighty degrees and the measure of angle C is x.
Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
4 0
Triangles have, naturally, 3 angles. The sum of all 3 angles will always be 180 degrees, no matter the triangle. Angles A + B + C will always equal 180 degrees.

55 + 80 + x = 180
x = 180 - 80 - 55
x = 45°
bulgar [2K]3 years ago
3 0

Answer:

45

Step-by-step explanation:

because 180-55-80 =45

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3 years ago
Grady drove 34 miles to his grandmas house. Next he drove 48 miles to visit his uncle. The trip took 90 minutes. If he drove at
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55 mph

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2 years ago
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6 0
3 years ago
If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
S_A_V [24]
Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
3 0
3 years ago
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