Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer:
Rate of change of the area of the rectangle at that instant = 7 cm²/hr.
Step-by-step explanation:
Area of rectangle = Height x Width
A = hw
The height of a rectangle is increasing at a rate of 3 centimeters per hour and the width of the rectangle is decreasing at a rate of 4 centimeters per hour.

Differentiating area with respect to time,

We need to find rate of change of area when the height is 5 centimeters and the width is 9 centimeters.

Rate of change of the area of the rectangle at that instant = 7 cm²/hr.
The original prize: 14.649
New prize: 23.609
(the years here are not relevant, just to confuse you with more numbers)
the increase is 23.609-14.649=8.960
If we want to know the percentage, we need to know what percentage of the original prize is 8.960.
this is calculated like this:

ti make it into percentage, we multiply by 100%: 61.164%
<h3>
Answer: 29 goes in the box</h3>
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Explanation:
The two endpoints are (-3,1) and (-1,-4)
Apply the distance formula

So the approximate distance is roughly 5.38 units and the exact distance is
units.
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As a slight alternative, you can plot the point (-3,-4) and draw a right triangle. Then apply the pythagorean theorem to find the length of the hypotenuse. The vertical and horizontal legs are 5 and 2 units respectively.
It turns out that the distance formula is essentially a modified form of the pythagorean theorem.