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iVinArrow [24]
3 years ago
7

It costs $45 to rent a car each day. There is also a fee of $12. How much does it cost to rent a car for 5 days,including the fe

e? Write an equation for each problem. Use a variable for the unknown. Solve.
Mathematics
2 answers:
vitfil [10]3 years ago
8 0

The equation is 12 + (45n)  n is number of days.

$12 + ($45*5)= $12 + $225= $237

goblinko [34]3 years ago
8 0

Answer:

An equation for each problem is y = 12+45x

The total cost for 5 days is $237

Step-by-step explanation:

Rent per day of car = $45

Let x be the no. of days

Rent for x days = 45x

There is also a fee of $12

So, Total cost for x days = 12+45x

Let y denotes the total cost

An equation for each problem is y = 12+45x

Substitute x = 5

y = 12+45(5)

y = 237

Hence the total cost for 5 days is $237

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Answer:

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Step-by-step explanation:

9) y=\frac{3}{5} x +5

10) y = x - 3

11)  y=-\frac{3}{5} x - 3

12) y=\frac{5}{4} x + 2

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2 years ago
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algol13
Equation: 17 + x = 23
To solve this you would do 23 - 17 to get x
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3 years ago
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Help please
exis [7]

Answer:

You can put this solution on YOUR website! 5X - 20 = 10 * X 5X - 20 = 10X Subtract 5x from each side-20 = 5X Divide each side by 5-4 = X. Let's make sure it works... 20 less than five times a number (-20-20) is equal to the product of ten and that number (10 * -4)

Step-by-step explanation:

8 0
2 years ago
Solve: x2 − x − 6/x2 = x − 6/2x + 2x + 12/x After multiplying each side of the equation by the LCD and simplifying, the resultin
Vesna [10]

The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}

Multiply both the sides by x.

\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}

Again multiply both the sides by x

2x^{2} -2x-12 = 5x^{2} +18x

\implies 5x^{2} -2x^{2} +18x +2x +12 = 0

\implies 3x^{2} + 18x+2x + 12 = 0

Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

Find out more information about equation here:

brainly.com/question/2976807

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1 year ago
How would the following triangle be classified?
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Answer:

hope this helpful

Step-by-step explanation:

isosceles right

because A light ray incident at 90° at the first face emerges at the same angle. The diagram shows five isosceles right-angled prisms. A light ray incident at 90° at the first face emerges at the same angle with the normal from the last face.

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