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iVinArrow [24]
3 years ago
7

It costs $45 to rent a car each day. There is also a fee of $12. How much does it cost to rent a car for 5 days,including the fe

e? Write an equation for each problem. Use a variable for the unknown. Solve.
Mathematics
2 answers:
vitfil [10]3 years ago
8 0

The equation is 12 + (45n)  n is number of days.

$12 + ($45*5)= $12 + $225= $237

goblinko [34]3 years ago
8 0

Answer:

An equation for each problem is y = 12+45x

The total cost for 5 days is $237

Step-by-step explanation:

Rent per day of car = $45

Let x be the no. of days

Rent for x days = 45x

There is also a fee of $12

So, Total cost for x days = 12+45x

Let y denotes the total cost

An equation for each problem is y = 12+45x

Substitute x = 5

y = 12+45(5)

y = 237

Hence the total cost for 5 days is $237

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The correct works are:

  • Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3.
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<h3>Function Notation</h3>

The function is given as:

Blue(s) = 2s^2 + 3

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

Blue(s + h) = 2(s + h)^2 + 3

Evaluate the exponent

Blue(s + h) = 2(s^2 + 2sh + h^2) + 3

Expand the bracket

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

So, the correct work is:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

Blue(s) = 2s^2 + 3

The difference quotient is represented as:

\frac{f(x + h) - f(x)}{h}

So, we have:

\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}

Evaluate the like terms

\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}

Evaluate the quotient

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Hence, the correct work is:

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Read more about function notations at:

brainly.com/question/13136492

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