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Basile [38]
3 years ago
11

I'm new here could someone help.

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0
<span>D. ∠THI≅∠PGA is the correct answer

</span>
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How do you solve (Arc)QPT if &lt;QZT = 120
yuradex [85]
By definition, the arc length is given by:
 arc = R * theta * ((2 * pi) / 360)
 Where,
 theta: angle in degrees
 R: radio
 We have then:
 (Arc) QPT if <QZT = 120:
 theta = 360-120 = 240 degrees
 R = 13.5 units
 Substituting values we have:
 (Arc) QPT = R * theta * ((2 * pi) / 360)
 (Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
 (Arc) QPT = 56.55 units
 Answer:
 
(Arc) QPT = 56.55 units
7 0
3 years ago
Davis is buying a new car for $21,349.00.He plans to make a down payment of $3,000.00.If he's to make monthly payments of $352 f
nekit [7.7K]
He actually borrowed P=21349-3000=18349 (present value)
Assume the monthly interest is i.
then future value due to loan:
F1=P(1+i)^n=18349(1+i)^(5*12)=18349(1+i)^60
future value from monthly payment of A=352
F2=A((1+i)^n-1)/i=352((1+i)^60-1)/i
Since F1=F2 for the same loan, we have
18349(1+i)^60=352((1+i)^60-1)/i
Simplify notation by defining R=1+i, then
18349(R^60)-352(R^60-1)/(R-1)=0
Simplify further by multiplication by (R-1)
f(R)=18349*R^60*(R-1)-352(R^60-1)=0
Solve for R by trial and error, or by iteration to get R=1.004732
The APR is therefore
12*(1.004732-1)=0.056784, or 5.678% approx.




8 0
3 years ago
The hypotenuse of a right triangle is 7 feet long. One leg is 4 feet longer than the other. Find the lengths of the legs, Round
Andrews [41]

Answer:

Shorter leg = 2.5 ft.

Longer leg = 6.5 ft.

Step-by-step explanation:

a^2 + b^2 = c^2

Because the hypotenuse = 7 ft, a^2 + b^2 = 49

To represent the two legs, we can use x and x+4.

x^2 + (x+4)^2 = 49

Simplifying this equation using FOIL gives us 2x^2 + 8x - 33 = 0.

Then, using the quadratic formula, we find that x = 2.5.

Thus, the shorter leg is 2.5 ft. and, when 4 is added, the longer leg is 6.5 ft.

5 0
3 years ago
True or false - A reflection is an example of a rigid transformation?
Ray Of Light [21]
True
Lengths are preserved during a reflection, meaning it is rigid.
4 0
3 years ago
Error Analysis: Pedro compares 7/33 and 2/11. He incorrectly says 7/33 &lt; 2/11 because 4.71 &lt; 5.50. Compare 7/33 and 2/11.
madreJ [45]
He divided the wrong way.  7/33 = .2121.....and 2/11 = .1818...., so actually 2/11 < 7/33
5 0
3 years ago
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