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chubhunter [2.5K]
3 years ago
8

X^2+16x+63=0 enter the solutions from least to greatest

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
X1=-9 X2=-7
First factor the equation to (x+9) • (x+7)=0
Then separate x+9=0 x+7=0 then solve for x
-9,-7.
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2/3÷2 1/3= dividing fractions
wolverine [178]

Answer:

3/3

Step-by-step explanation:

3/3

4 0
2 years ago
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Delaney bought a crate for her puppy when it was 3 months old. The crate is in the shape of a rectangular prism. Since the puppy
Alika [10]

Answer:

The volume of the new crate is exactly 174.4% of the old crate.

Step-by-step explanation:

Volume of a rectangular prism:

The volume of a rectangular prism of dimensions x, y and z is given by:

V = xyz

She decided that the dimensions of the new crate needs to be increased by 40% of the original length.

Each dimension is increased by 40%, which means that each is multiplied by 1 + 0.4 = 1.4. So

V = 1.4x(1.4y)(1.4z) = (1.4)^3(xyz) = 2.744(xyz)

Percentage:

The new volume is 2.744 the original volume. Considering the original volume is 100% = 1, it increased by 2.744 - 1 = 1.744 = 1.744*100% = 174.4%.

The volume of the new crate is exactly 174.4% of the old crate.

7 0
2 years ago
Please help! 11 pts.
77julia77 [94]
Hey user!!!

given the radius of the cylindrical mold is 2 inches and height is 3 inches.

volume of the cylindrical mold = πr²h

= 3.14 × 2 × 2 × 3

= 37.68 in³


radius of the spherical mold is given = 2 inches

volume of the spherical mold = 4/3πr³

= 4/3 × 3.14 × 2 × 2 × 2

= 100.48/3 in³


difference between the amount of wax needed = 37.68/1 - 100.48/3

= ( 113.04 - 100.48 ) / 3

= 12.56/3

= 4.186...

so approximately 4.19 in³

hence, correct option is 4.19 in³


cheers!!!
8 0
3 years ago
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Ostrovityanka [42]

Answer:

Add all of them together. 1/5 + 2/4 + 4/3 + 3/2 = 53/15 miles

Step-by-step explanation:

1/5 + 2(1/4) + 4(1/3) + 3(1/2)

3 0
2 years ago
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weqwewe [10]
I don’t really understand this put a person with genius role is answering so i hope you get your answer! goodluck
8 0
2 years ago
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