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marusya05 [52]
2 years ago
7

Jeffrey is n years old. His sister is 5 years older than Jeffrey’s age. Write an expression that represents the relationship of

his sister’s age in terms of Jeffrey’s age, where n represents Jeffrey’s age. I need help ASAP PLEASE!!
Mathematics
1 answer:
weqwewe [10]2 years ago
8 0

Answer:

jeffreys sister is 5+n

Step-by-step explanation:

so practically jefferys sister is N or jefferys age plus 5

hope this helped

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4. If DF = 9x - 39, find EF.<br><br> Help I’m so confused!!!!
topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

<em>give</em><em>n</em><em> </em><em>that</em><em> </em><em>DF</em><em> </em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>,</em><em> </em><em>DE</em><em> </em><em>=</em><em>4</em><em>7</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em>

<em>sub</em><em>stitute</em><em> </em><em>them</em><em> </em><em>into</em><em> </em><em>the</em><em> </em><em>formu</em><em>la</em><em>,</em>

<em> </em><em> </em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>-</em><em> </em><em>4</em><em>7</em>

<em>sol</em><em>ving</em><em> </em><em>for</em><em> </em><em>x</em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em> </em><em>=</em><em>9</em><em>x</em><em> </em><em>-</em><em>8</em><em>6</em>

<em>grou</em><em>ping</em><em> like</em><em> </em><em>ter</em><em>ms</em>

<em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>9x</em><em> </em><em>=</em><em>-</em><em>8</em><em>6</em><em> </em><em>-</em><em>1</em><em>0</em>

<em>-6x</em><em>=</em><em>-</em><em>9</em><em>6</em>

<em>div</em><em>iding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>-</em><em>6</em>

<em>\frac{ - 6x}{ - 6}  =  \frac{ - 96}{ - 6}</em>

<em>x  =  \frac{96}{6}</em>

<em>x = 16</em>

<em>but</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em>+</em><em>1</em><em>0</em>

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

6 0
3 years ago
Read 2 more answers
Please Help! Malik agreed to practice basketball drills with a new player, Tyler, during practice. Malik's best friend, Samuel,
lions [1.4K]
Malik can remain honest with his partner Samuel and respect his opinion.
3 0
2 years ago
A toy rocket is lunch vertically upward from ground level in into velocity of one 28 ft./s how long will it take for the rocket
pentagon [3]

Answer:

1.14 s

Step-by-step explanation:

Time, t=\frac {d}{s}

Here, d is the distance and s is the speed/velocity

Since we're given the velocity, s as 28 ft/s and the distance between the position of the rocket and ground as 32 ft then

t=\frac {32}{28}=1.142857143\approx 1.14 s

Therefore, it needs 1.14 seconds

4 0
3 years ago
Read 2 more answers
Factor the expression 20k + 50
Yuliya22 [10]
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
4 0
3 years ago
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
3 years ago
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