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3 years ago

3w-4z=8 2w+3z=-6 solve

Mathematics

1 answer:

marissa [1.9K]3 years ago

4 0

Answer:

W = 0

Z = -2

Step-by-step explanation:

While simplyfying the equation, i noticed that one is 24 and the other is -24, which meant that one value is non existent, and after i found out that w = 0 imputing the reslut made that easier

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To reach a vacation spot, the Jones family first traveled by plane and then drove the

navik [9.2K]

The distance flown by plane is 750 kilometers.

Step-by-step explanation:

Let,

Distance traveled by plane = x

Distance traveled by car = y

Total distance = x+y

According to given statement;

The distance by car was 125 kilometers less than the distance by plane.

y = x - 125 => x=y+125 Eqn 1

The total distance was 500 kilometers less than three times the distance traveled by car.

Total distance = 3y - 500

x+y=3y-500 Eqn 2

Putting value of x from Eqn 1;

$(y+125)+y=3y-500\\y+y+125=3y-500\\2y=3y-500-125\\2y-3y=-625\\-y=-625\\y=625$

Putting y=625 in Eqn 1

$x=625+125\\x=750$

The distance flown by plane is 750 kilometers.

Keywords: linear equations, substitution method

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

G=3j+4 for j how do I find r

musickatia [10]

Answer:

Step-by-step explanation:

thats the answer i did it too

7 0

3 years ago

A quadrilateral with vertices C(−6, 6), D(−1, 10), E(5, 8), F(0, 4) is a parallelogram.

Usimov [2.4K]

Answer:

m = (y2 - y1) / (x2 - x1) = (10 - 6) / (-1 - (-6)) = 4 / 5 = 0.8

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3 years ago

Find the quotient of 68.0052 and 12. Round your answer to the nearest hundredth

Vlad1618 [11]

68.01
A quotient is the answer to two numbers being divided.
Meaning 68.0052÷12 is 68.01

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4 years ago

What is the general form of the equation of a circle with center at (a, b) and radius of length m?. A. x2 + y2 − 2ax − 2by + (a2

drek231 [11]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{a}{ h},\stackrel{b}{ k})\qquad \qquad 
radius=\stackrel{m}{ r}
\\\\\\
\boxed{(x-a)^2+(y-b)^2=m^2}\\\\
-------------------------------\\\\
(x^2-2ax+a^2)+(y^2-2yb+b^2)=m^2
\\\\\\
x^2-2ax+a^2+y^2-2yb+b^2-m^2=0
\\\\\\
x^2+y^2-2ax-2yb+(a^2+b^2-m^2)=0$

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4 years ago