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Vaselesa [24]
3 years ago
12

Matrix P is shown below. Given that Matrix P equals Matrix Q, what is the value of q33

Mathematics
2 answers:
Nesterboy [21]3 years ago
3 0

Given\:matrix\:\begin{pmatrix}1.1&3.5&-9\\ -8.1&0&6.2\\ 2&7&16\end{pmatrix}.

We need to find q_{33}.

q_{33} represents, the element of third row and third column.

We would go third row that has elements 2 7 16 and

third column has elements -9 6.2 16.

We can see that element of third row and third column is 16.

<h3>Therefore, correct option is fourth option 16 in the given options.</h3>

Blizzard [7]3 years ago
3 0

Answer:

D

Step-by-step explanation:

E2020

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They each get 1/8 of the brownie

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Help me with this sum please
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Volume=length times width times height
this should be easy

a.
the volume of a box is 2.5 times 1 times 1 or 2.5 cubic meters

b.
number of boxes times volume per box=volume of container
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4 0
3 years ago
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3 years ago
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mixas84 [53]
A number is used as a factor about 5 times
5 0
4 years ago
Find the exact value of the trigonometric expression given that sin(u) = -(3/5),
GuDViN [60]

Recall that

\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}

Also, recall that for all \theta,

\cos^2\theta+\sin^2\theta=1

With \frac{3\pi}2, we can expect \cos u>0, and with 0, \sin v>0. So from the above identity it follows that

\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43

and

\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8

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6 0
3 years ago
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