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Bad White [126]
4 years ago
10

Am I correct? If not what did I do wrong

Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
5 0

    You are not correct. Here's an explanation as to why: First of all, the triangle is isosceles, since it has two congruent sides that leads to the conclusion of two congruent angles, one opposite each side. This means that all three angle measurements of the triangle are x degrees, x degrees, and 40 degrees. To solve for x, add all three values together and set them equal to 180 degrees, the sum of three angles in any triangle. Your mistake is adding only one x to 40, which isn't inclusive of all three triangles. I hope this helped!

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For a recently released movie, the function y = 119.67(0.61)x models the revenue earned, y, in millions of dollars each week, x,
Marina CMI [18]
Given:
Function y = 119.67(0.61)x

x = week 3.

F(3) = 119.67(0.61)(3)
F(3) = 119.67*1.83
F(3) = 218.9961

x = week 5

F(5) = 119.67(0.61)(5)
F(5) = 119.67 * 3.05
F(5) = 364.9935
4 0
4 years ago
Which expression is undefined?
kari74 [83]

Answer:

C. 4/0

Step-by-step explanation:

You can't divide 4 by 0.

A. you would have gotten -0.5

B. you would have gotten 0

D. you would have gotten 0

Hope this help!! :)

3 0
3 years ago
Read 2 more answers
Which of the following is not one of the 8th roots of unity?
Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1.  Since z=1=1+0\cdot i, then

Rez=1,\\ \\Im z=0

and

|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.

This gives you \varphi=0.

Thus,

z=1\cdot(\cos 0+i\sin 0).

2. The 8th roots can be calculated using following formula:

\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.

Now

at k=0,  z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;

at k=1,  z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=2,  z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;

at k=3,  z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=4,  z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;

at k=5,  z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

at k=6,  z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;

at k=7,  z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

The 8th roots are

\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.

Option C is icncorrect.

5 0
3 years ago
Write the expression: the quotient of the quantity k minus 12 and m. A) 12 − m k B) m − 12 k C) 12 − k m D) k − 12 m
Len [333]

Answer:

Option D) (k − 12)/m                          

Step-by-step explanation:

We have to write an expression:

the quotient of the quantity k minus 12 and m.

k minus 12 can be written as:

k - 12

The quotient of (k-12) and m means (k-12) is divided by m.

This can be written as:

\dfrac{k-12}{m}

Thus, the correct answer is

Option D) (k − 12)/m                                                                      

4 0
4 years ago
Question 13 please help& give explanation if possible thank u
Lisa [10]

Answer:

Step-by-step explanation:

7 0
3 years ago
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