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Advocard [28]
2 years ago
12

Movie tickets are $4.00 for children and $8.00 for adults. The total amount of ticket sales in one night was $1,176. There was 1

72 tickets sold.
Define the variables used in this example.





Your answer:

m= money

t=tickets


c=children

a= adults


t= tickets


c=children
Mathematics
2 answers:
sleet_krkn [62]2 years ago
7 0

Answer:

122 tickets were sold for adults and the rest is for children.

Step-by-step explanation:

Liono4ka [1.6K]2 years ago
5 0

Answer: Cant answer this question because the question doesnt say/contain how many children were there and how many parents were there. if you list this, i can help

Step-by-step explanation:

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suppose a population of 250 crickets doubles in size every six months. How many crickets will there be after two years?
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double every 6 months 

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Step-by-step explanation:

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4 0
2 years ago
6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

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n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0
2 years ago
Read 2 more answers
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