Answer:
Step-by-step explanation:
A box contains four cards: One card is black on both sides, one card is red on both sides and two cards are black on one side and red on the other side. One card is selected at random and you can see only one side.i) If the side you see is black, what is the probability that the other side is black?ii) If the side you see is black, what is the probability that the other side is red?
Given that:
Number of cards = 4
x = Black on both sides = 1
y = Red on both sides = 1
z = Black on one side, red on one side = 2
.i) If the side you see is black, what is the probability that the other side is black = b
Probability of black
P(x) = 1/4 ; p(b|x) = 1
P(y) = 1/4 ; p(y|x) =
9514 1404 393
Answer:
A. no solution
Step-by-step explanation:
The solution is found where the lines meet. Parallel lines never meet, so there is no solution.
We have that
<span>A (-8, -2) and B(16,6)
step 1
find the distance AB in the x coordinates
dABx=(16-(-8))-----> 24 units
step 2
find coordinate x of P (Px)
Px=Ax+(3/5)*dABx------> Px=(-8)+(3/5)*24----> 6.4
step 3
F</span>ind the distance AB in the y coordinates
dABy=(6-(-2))-----> 8 units
step 4
find coordinate y of P (Py)
Py=Ay+(3/5)*dABy------> Py=(-2)+(3/5)*8----> 2.8
the coordinates of P are (6.4,2.8)
see the attached figure
I think you can put bench mark place valie round tenth thousnadth
A)
145 - 5d
5d = 145, set equal
29 days to lay all the track
b)
5*19 = 95
145-95 = 50
After 19 days, they have 50 miles to go.