Given:
40 pages in 1.6 minutes

40 / 1.6 = 25 pages per minute

25 x 5 minutes = 125 pages

40 / 1.6 = x / 5
40*5 = 1.6x
200 = 1.6x
200/1.6 = x
125 = x pages

25 : 1 = 150 : x
25x = 150
x = 150/25
x = 6 minutes

4 0

3 years ago

A new battery's voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries wil

klio [65]

Answer:

The probability that you test exactly 4 batteries is 0.0243.

Step-by-step explanation:

We are given that a new battery's voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries will be independently selected and tested until two acceptable ones have been found.

Suppose that 90% of all batteries have acceptable voltages.

Let the probability that batteries have acceptable voltages = P(A) = 0.90

So, the probability that batteries have unacceptable voltages = P(U) = 1 - P(A) = 1 - 0.90 = 0.10

Now, the probability that you test exactly 4 batteries is given by the three cases. Firstly, note that batteries will be tested until two acceptable ones have been found.

So, the cases are = P(AUUA) + P(UAUA) + P(UUAA)

This means that we have tested 4 batteries until we get two acceptable batteries.

So, required probability = (0.90 $\times$ 0.10 $\times$ 0.10 $\times$ 0.90) + (0.10 $\times$ 0.90 $\times$ 0.10 $\times$ 0.90) + (0.10 $\times$ 0.10 $\times$ 0.90 $\times$ 0.90)

= 0.0081 + 0.0081 + 0.0081 = 0.0243

Hence, the probability that you test exactly 4 batteries is 0.0243.

3 0

3 years ago