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Taya2010 [7]
3 years ago
12

Factoring polynomials ps I need help

Mathematics
1 answer:
Semenov [28]3 years ago
5 0

Answer:

4m^2-3mn^2+5

Step-by-step explanation:

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Radius(p) = 2.75/2

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3x+10

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Given f(x) = -* -<br> - 5, solve for x when f(x) = -3.
Ne4ueva [31]

Answer:

x = -2

Step-by-step explanation:

Step 1: Define

f(x) = -x - 5

f(x) = -3

Step 2: Substitute and Evaluate

-3 = -x - 5

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The total price of a shirt and a cap is $11. If the price of the shirt was doubled and the price of the cap was three times its
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the shirt is 8 dollars and the cap is 3

Step-by-step explanation:

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4 0
2 years ago
Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.
nadya68 [22]

Answer:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given X_(1), X_(2) ,..., X_(n) and for each observation X_i \sim N(\mu, \sigma) since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is X_(n) and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0
3 years ago
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