Answer:
d. parabola, 0°
Step-by-step explanation:
y² + 8x - 0
y² = -8x
Where x = cos t , y = sin t
Sin² t = -8 Cos t
1 - Cos² t = -8 Cos t
- Cos² t + 8 Cos t + 1 = 0
t = 2лπ ± (3 + √10) , л∈Z
Angle of rotation
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
Answer:
16/3
Step-by-step explanation:
