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3 years ago

Solve for a in terms of F and m: F=ma

1 answer:

Elena-2011 [213]3 years ago

5 0

To solve for a, you must get a by itself on one side of the equation. Now, a is "joined" to m by multiplication. To "separate" them, use the inverse operation, division.

Divide both sides of the equation by m.

$F=ma \\ \frac{F}{m}=\frac{ma}{m} \\ \frac{F}{m}=a \\ a=\frac{F}{m}$

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Does anyone know how to do this help please

statuscvo [17]

Answer:

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

Step-by-step explanation:

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$\rm\implies y = 3^2-3-6\\$

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$\rm\implies y = 2^2-2-6\\$

$\rm\implies y = 4 -2-6\\$

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Put x = -1 :-

$\rm\implies y = -1^2-1-6\\$

$\rm\implies y = 1 -1-6 \\$

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Put x = 1 :-

$\rm\implies y = 1^2+1-6\\$

$\rm\implies y = 2 -6$

$\rm\implies y = -4$

Put x = 2 :-

$\rm\implies y = 2^2+2-6\\$

$\rm\implies y = 4 +2-6\\$

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Put x = 3 :-

$\rm\implies y = 3^2+3-6\\$

$\rm\implies y = 9 +3-6\\$

$\rm\implies y = 6$

Final table :-

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

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