You need the distance formula to figure this out. The coordinates for point D are (-5, 1), the coordinates for point E are (-2, 3), and the coordinates for point F are (-3, -2). For the distance or length of DE, the formula looks like this:

which simplifies a bit down to

which is

which of course is

so DE = 25. Moving on to EF:

which simplifies to

which is to say that

. We do the same for FD:

which simplifies a bit to

which is to say that the length of FD is

. None of the lengths of the sides are the same, so this is a scalene triangle. Last choice given above.