All categories

3 years ago

HELP NOW EXTRAA 20 POINTS

Mathematics

1 answer:

Nesterboy [21]3 years ago

3 0

Answer:

14x + x^2

------------------

9x^2

Step-by-step explanation:

2x /x^2 + (x-4)/ 9x

Cancel the common factor of x in the first term

2 /x + (x-4)/ 9x

We need a common denominator of 9x

2 /x *9/9 + (x-4)/ 9x

18/9x + (x-4)/9x

Add the numerators

18+x-4

--------------

14+x

----------

Multiply the top and bottom by x to get it to match one of the answers

14x + x^2

------------------

9x^2

You might be interested in

Simplify the expression 8+10p-4-7p

Andrews [41]

Answer: the answer is 4+3p

7 0

3 years ago

What is the simplified form of 5√x• 5√x•5√x•5√x

ella [17]

Answer:

i could be wrong but (5√x)^3

Step-by-step explanation:

im ot sure though

4 0

3 years ago

Read 2 more answers

When new, a standard tire has 10/32 inches of tread. When only 2/32 inches of tread remains, the tire needs to be replaced. If t

san4es73 [151]

Answer:

$\frac{1}{160} \ inches$

Step-by-step explanation:

The computation of the thickness of tire rubber for every lost 1,000 driven is shown below:

Data provided in the question

Inches of tread = $\frac{10}{23}$

In case of replaced = $\frac{2}{3}$

Based on the above information

Now in 40,000 miles, the ratio is

$= \frac{10 - 2}{32} \\\\ = \frac{1}{4}$

And for every 1,000 miles driven, the thickness is

$= \frac{1}{4 \times 40,000} \times 1,000 \\\\ = \frac{1}{160} \ inches$

hence, the thickness of tire rubber is $\frac{1}{160} \ inches$

7 0

3 years ago

Can someone help me with this math problem?

Alexus [3.1K]

The area of ΔIDK is 32.69 square units.

Solution:

Given data:

ID = 7 and Hypotenuse, KI = 11.67.

Let us first find KD:

Using Pythagoras theorem,

$\text {Base}^{2}+\text {Height}^{2}=\text {Hypotenuse}^{2}$

$ID^2 + KD^2 = KI^2$

$7^2 + KD^2 = (11.67)^2$

$49 + KD^2 = 136.1889$

Subtract 49 from both sides.

$KD^2=87.1889$

Taking square root on both sides, we get

KD = 9.34

Area of the triangle = $\frac{1}{2}\times\text{base}\times\text{height}$

$$=\frac{1}{2}\times{7}\times{9.34}$

= 32.69

The area of ΔIDK is 32.69 square units.

7 0

3 years ago

Pls help! Write two inequalities for the graph.<br> (System of inequalities)

Y_Kistochka [10]

Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

5 0

3 years ago