(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15
Answer:
The cost of 1 sparkling bottle in this week is less than last week, so we pay less this week.
We pay $0.44 less this week.
Step-by-step explanation:
Given,
Cost of 1 sparkling bottle last week = $1.69
This week cost of 4 bottles is $5.
So we have to find the cost of 1 bottle.
For this we use the unitary method, we get the cost of 1 bottle;
Cost of 1 sparkling bottle this week = 
The cost of 1 sparkling bottle in this week is less than last week, so we pay less this week.
For finding how much we pay less this week, we have to subtract cost of 1 sparkling bottle this week from cost of 1 sparkling bottle last week.
Framing the above sentence in equation form, we get;
Hence we pay $0.44 less this week.
Answer:
one solution
Step-by-step explanation:
3x − 7 = 4 + 6 + 4x
Combine like terms
3x-7=4x+10
Subtract 3x from each side
-7=x+10
Subtract 10 from each side
-17 =x
There is one solution
Answer:
103.67 in³
Step-by-step explanation:
given Volume of cone is 1/3 * π * r² * h
here given r = 6/2 = 3 , height = 11 inch
using the formula = 1/3 * π * 3² * 11
=103.67 in³ or 33π in³
Answer:
3,750 cars.
Step-by-step explanation:
We are given that the equation:

Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.
We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.
When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:

Solve for <em>x</em>. Subtract 9000 from both sides:

Divide both sides by -2.4:

So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.