Question

Professor Melendez has 10 students in her college

Answer 1

Answer:

Mean = 18.625

Median = 18.5

Step-by-step explanation:

Given the following :

Age = 19, 27, 19, 18, 18, 18, 47, 19, 20, 18

The mean Age :

Mean = Σ(x) ÷ N

N = number of data

(19 + 27 + 19 + 18 + 18 + 18 + 47 + 19 +20 + 18) / 10

Σ(x) / N = 223/10 = 22.3

Rearranging to get the median:

18,18,18,18,19,19,19,20,27,47

Middle value = median ( 19 + 19)/2 = 19

The outliers in the data are:

18,18,18,18,19,19,19,20,27,47

OUTLIERS ARE VALUES

< Q1 - (1.5 × IQR)

> Q3 + (1.5 × IQR)

IQR = Q3 - Q1 (Interquartile range)

Q3 = upper quartile

Q1 = lower quartile

From the data :

Q3 = 20, Q1 = 18

IQR = Q3 - Q1 = 20 - 18 = 2

< 18 - (1.5 × 2) ; <15

> 20 + (1.5 × 2) ; >23

VAlues greater than 23 and less than 15 are outliers in the data

27 and 47

After removing outliers

N = 10 - 2 = 8

Σ(x) = 223 - (47+27) = 149

Mean = 149/8 = 18.625

X = 18,18,18,18,19,19,19,20

Median = (18 + 19)/2 = 18.5