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netineya [11]
3 years ago
14

Solve the following inequality fort:

Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

$t

it seems that the answer didn't match the alternatives. But t < 1 is true.

If t > 1:

So, considering t = 2

$5-4(2)>\frac{3-2}{2} $

$5-8>\frac{1}{2} $

$-3>\frac{1}{2} $

This is not true.

Step-by-step explanation:

Given inequality:

$5-4t>\frac{3-t}{2} $

$2(5-4t)>\frac{3-t}{2} \cdot 2$

$10-8t>3-t$

$-8t+t>3-10$

$-7t>-7$

Dividing both sides by -7 will led to the flip of the inequality symbol.

$t

Considering t = -1

$5-4(-1)>\frac{3-(-1)}{2} $

$5+4>\frac{3+1}{2} $

$9>\frac{4}{2} $

$9>2 $

That's right

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Area of a rectangle

= l \times w

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4 0
3 years ago
Given y-k=a(x-h)^2, a=-1, h&gt;0, k&lt;0 in which quadrant is the vertex
ad-work [718]

Answer:

Since the equation is a quadractic, the graph would be a parabola.

With a being -1, the parabola will represent a reflection of the y values. In other words, the parabola will be upside down and the vertex will be a maximum value. Ultimately, the <em>a </em>in the function doesn't determine the location of the vertex.

Since the k value is negative, that means the equation begins <em>y - (-k)</em>. The K value being negative restricts the transformation of the parabola to being down <em>k</em> number of units. The location of moving the parabola down places the vertex in the third or fourth quadrant.

The <em>h</em> value being positive means that the parabola is shifted to the right <em>h</em> number of units. For example, if the parabola <em>f(x) = x²  </em>has a vertex at (0,0), the parabola <em>f(x) = (x-2)²</em> must have a vertex at (2,0) because 2 - 2 = 0. Shifting right places the vertex of the parabola in the first or fourth quadrant.

Therefore the k value and h value restrictions must overlap in the fourth quadrant.

Step-by-step explanation:


5 0
3 years ago
7. Find another rational number in lowest form that would be between each of the pairs of rational
Marianna [84]
6:3!)4 hope it helps
3 0
3 years ago
80 POINTS!!!!<br><br> Simplify 6 to the power of -3 over 6 to the power of 5
tigry1 [53]

6^-3 / 6^5

Because the numerator has a negative exponent, use the negative exponent rule b^-n = 1/b^n

To do this move 6^-3 to the denominator:

1 / (6^5 * 6^3)

When you multiply identical numbers with exponents you add the exponents so (6^5 * 6^3) becomes 6^8

Now you have 1 / 6^8

Now raise 6 to the power of 8 to get:

1/1679616

Depending on the format your answer needs to be in you have 3 different answers:

1) 1/6^8 ( Leaving it as an exponent)

2) 1 / 1679616 (As a fraction)

3) 5.9537 x 10^-7 (As a decimal, round as needed)

5 0
4 years ago
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