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netineya [11]
3 years ago
14

Solve the following inequality fort:

Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

$t

it seems that the answer didn't match the alternatives. But t < 1 is true.

If t > 1:

So, considering t = 2

$5-4(2)>\frac{3-2}{2} $

$5-8>\frac{1}{2} $

$-3>\frac{1}{2} $

This is not true.

Step-by-step explanation:

Given inequality:

$5-4t>\frac{3-t}{2} $

$2(5-4t)>\frac{3-t}{2} \cdot 2$

$10-8t>3-t$

$-8t+t>3-10$

$-7t>-7$

Dividing both sides by -7 will led to the flip of the inequality symbol.

$t

Considering t = -1

$5-4(-1)>\frac{3-(-1)}{2} $

$5+4>\frac{3+1}{2} $

$9>\frac{4}{2} $

$9>2 $

That's right

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3 years ago
List the next four multiples of fraction 7/12
Sidana [21]
<h2>Hello!</h2>

The answer is:

\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5

<h2>Why?</h2>

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of \frac{7}{12} are:

\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}

Have a nice day!

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