Answer:

Step-by-step explanation:

 
        
             
        
        
        
Answer:
a
Step-by-step explanation:
 
        
             
        
        
        
Answer:
A
Step-by-step explanation:
We need to find a equation that is where the domain is all real numbers and the range is all real numbers greater than -3
- A square root function cannot equal to all real numbers because we cant take the square root of a negative number. so B and C are already wrong.
- A cubic function range is all real numbers. so y can be greater than -3 but it would also include. values lesser than -3. so D is Wrong.
A is right, the domain of a absolute value function is all real numbers. The range of a absolute value is all numbers greater than or equal to zero but if we subtract 3, it changes into all real numbers greater than or equal to -3
 
        
             
        
        
        
<h3>
Answer: Choice D.  g(x) = 3|x-3| - 6</h3>
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Explanation:
Points are of the form (x,y), where y = f(x) since y and f(x) are outputs.
When we vertically stretch by a factor of 3, we are making the function curve 3 times more stretched out along the vertical y axis. So a general point (x,y) becomes (x,3y). Whatever the y coordinate is, we multiply by 3 to get its stretched out counterpart.
Eg: (0,-2) on f(x) moves to (0,-6) which is on g(x)
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Since y = f(x), and we're multiplying y by 3, we can say
f(x) = |x-3| - 2
3*f(x) = 3*( |x-3| - 2 )
3*f(x) = 3|x-3| + 3(-2)
3*f(x) = 3|x-3| - 6
g(x) = 3|x-3| - 6