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kramer
3 years ago
9

3. Leo wants to paint a mural that covers

Mathematics
1 answer:
forsale [732]3 years ago
3 0
My exact answer is 57.6
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Write the polynomial in standard form. Then identify the polynomial by the number of terms -5x^2-2x^3-4x
iVinArrow [24]
Hello :
-5x^2-2x^3-4x =-2x^3-5x^2-4x.....(<span> standard form.)
</span><span>the number of terms are : -2 , -5 , -4 ,0</span>
7 0
3 years ago
Please help this is the last problem on my homework and I don’t understand how to do it
malfutka [58]
When the lines are parallel and angles are given, and since a straight line is 180°, the 2 angles of the line intersecting the parallel lines have to add up to be 180. Therefore,
21. 31°
22. 96°
23. 149°
24. 84°
25. 53°
6 0
3 years ago
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The square of the binomial x-4 has the form x^2-ax+16. What is the value of a?
tia_tia [17]
A=-8x
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7 0
2 years ago
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Kalon and his friend Marna own a chimney sweep service company. Working together, they can clean a chimney in 1 5/7 hours. If it
aleksley [76]
So to set up the equation we have: <span><span><span>4M</span><span>4+M</span></span>=<span>127</span></span>
<span>28M=12(4+M)</span>
<span>28M=48+12M</span>
<span>28K−12M=48</span>
<span>(28−12)M=48</span>
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5 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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