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kramer
3 years ago
9

3. Leo wants to paint a mural that covers

Mathematics
1 answer:
forsale [732]3 years ago
3 0
My exact answer is 57.6
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$2 :) !!!!!!!!!!!!!!!!!!!!!!!!!
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3 years ago
i dont understand equations of parallel and perpendicular lines here's one of my teachers examples y=2x+4 (-2,1)
SIZIF [17.4K]
Parallel lines will never touch each other while perpendicular forms like an X shape. The slope for the parallel is the same while the perpendicular is a negative reciprocal. (Ex for negative reciprocal. 2/4=4/2)
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%202%5Cfrac%7B3%7D%7B4%7D%20%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexFormula1" title=" 2\fra
docker41 [41]

let's firstly, convert the mixed fraction to improper fraction, and then subtract.


\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\cfrac{11}{4}-\cfrac{2}{3}\implies \stackrel{\textit{our LCD will be 12}}{\cfrac{(3)11-(4)2}{12}}\implies \cfrac{33-8}{12}\implies \cfrac{25}{12}\implies 2\frac{1}{12}

8 0
4 years ago
What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare
Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

\text{Area of sector}=\frac{\theta}{360}\times \pi r^2, where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

\text{Area of sector}=\frac{138}{360}\times \pi (3)^2

\text{Area of sector}=\frac{138}{360}\times 9\pi

\text{Area of sector}=10.83849

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)

\text{Area of sector}=2(\frac{114}{360}\times 25\pi)

\text{Area of sector}=\frac{114}{360}\times 50\pi

\text{Area of sector}=49.74188

Let us find difference of area as shown below:

\text{Difference of areas}=49.74188-10.83849

\text{Difference of areas}=38.90339

\text{Difference of areas}\approx 38.9

Therefore, the difference in area covered is approximately 38.9 square inches.

8 0
3 years ago
H(x)=5/sqrt(2x+10), find the domain using set builder notation.
marissa [1.9K]

The given expression is

h(x) = \frac{5}{\sqrt{2x+10}}

THe given expression is a rational expression, and rational expression should not have 0 in the denominator.

Moreover, the denominator is a square root term, and square root don't have a value for negative number .

Therefore 2x+10 must be greater then 0. That is

2x+10>0&#10;\\&#10;2x>-10&#10;\\&#10;x>-5

Therefore the required domain in set builder form is

{x | x>-5}

4 0
4 years ago
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