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saul85 [17]
3 years ago
12

Without calculating, would 0.4 + (2 + 0.6) be less than, greater than, or equal to 3? Explain.

Mathematics
2 answers:
Anton [14]3 years ago
4 0

wqual because you round 0.6 to 1 and 0.4 to 0 so 2+1 is 3
grigory [225]3 years ago
3 0
Less than because 2 + 0.6 +0.4 would be 2.12 I think
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3 years ago
-10r-20=-20 i need help with this question​
svetoff [14.1K]

Answer:

r = 0

Step-by-step explanation:

To solve this for r, add 20 to both sides.  The result will be -10r = 0, and so

the solution is r = 0.

8 0
3 years ago
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A rhombus has a side length equal to one of the diagonals. The other diagonal is 4cm longer. Find the area of the rhombus.
klasskru [66]

Answer:

The area of the rhombus is 25.83 cm².

Step-by-step explanation:

The area of a rhombus is given by:

A = \frac{d_{1} \times d_{2}}{2}

Where:      

d₁: is one diagonal      

d₂: is the other diagonal = d₁ + 4 cm

We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:

h: hypotenuse of the right triangle  

a: one side of the right triangle

b: is the other side of the right triangle  

From the above we know that:

h = d₁                                

a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2}

b = \frac{d_{1}}{2}            

We can find d₁ with Pitagoras:

h^{2} = a^{2} + b^{2}  

d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2}

d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2})

By solving the above quadratic equation for d₁ and taking the positive solution we have:

d_{1} = 5.46 cm    

So, d₂ is:

d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm

Now, we can find the area:

A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2}

Therefore, the area of the rhombus is 25.83 cm².

I hope it helps you!  

3 0
3 years ago
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Ulleksa [173]

Answer:

1/20

Step-by-step explanation:

It's the same as doing 1/4 * 1/5, so 1/20.

8 0
3 years ago
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7nadin3 [17]

Answer:

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5 0
3 years ago
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