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Ne4ueva [31]
4 years ago
6

Which sequence is modeled by the graph below?

Mathematics
1 answer:
Andre45 [30]4 years ago
3 0

Answer:

I don’t know how to help you with that, that looks very confusing( the format of whatever type of equation that is)

Step-by-step explanation:

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What equation(s) represent joint variations? check all that apply c=2pi z=3x/y y=3x+2 w=abc/4 v=lwh
Alinara [238K]

Answer:

Step-by-step explanation:

Joint variations occurs when one variable depends on the value of two or more variables. The variable varies directly or indirectly with the other variables combined together. The other variables are held constant. From the given examples, the equation(s) that represent joint variations are

1) z = 3x/y

z varies directly with x and inversely with y.

2) w = abc/4

w varies inversely with a,b and c. 4 is the value of the constant of variation.

7 0
3 years ago
Find the perimeter of the object <br><br> Help step by step please!
aliina [53]

Answer:

29.42 units

Step-by-step explanation:

<u>1) Find the perimeter around the semi-circle</u>

To do this, we find the circumference of the circle using the given diameter:

C=\pi d where d is the diameter

Plug in 6 as the diameter

C=\pi (6)\\C=6\pi

Divide the circumference by 2

\frac{6\pi }{2} \\= 3\pi

Therefore, the perimeter around the semi-circle is 3π units.

<u>2) Find the perimeter around the rest of the shape</u>

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

20+3\pi \\= 20+9.42\\= 29.42

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

3 0
3 years ago
PLEASE HELP ITS OVERDUE PLEASE I NEED HELP!!
IgorLugansk [536]

Answer:

First question: Choice A

second question:Choice D

Third question: Choice c

Fourth question: Choise b

5th Question: choice b

5 0
3 years ago
(x + 1)^2 = 3x – 1 solving Quadratics ?
Deffense [45]

Step-by-step explanation:

(x + 1)^{2}  = 3x - 1 \\  \\  \therefore \:  {x }^{2}  + 2x + 1 = 3x - 1 \\  \\ \therefore \:  {x }^{2}  + 2x + 1  -  3x  + 1 = 0\\  \\ \therefore \:  {x }^{2}  + 2x  -  3x + 1 - 1 = 0 \\  \\ \therefore \:  {x }^{2}  - x  = 0 \\  \\ \therefore \:  x(x - 1) = 0 \\  \\ \therefore \: x = 0 \:  \: or \:  \: x - 1 = 0 \\  \\ \therefore \: x = 0 \:  \: or \:  \: x = 1 \\  \\  \huge{ \red{ \boxed{\therefore \: x =  \{0, \:  \: 1 \}}}}

5 0
4 years ago
Read 2 more answers
The area of the postcard is 24 square inches. What is the width b of the message (in inches)?
MAXImum [283]
Area of rectangular post card = length x width
For the given post card: 
length = 4 in
width = (3+b) in
area = 24 in^2

So, substituting in the equation of the area:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in

Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
4 0
4 years ago
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