How to solve this one ???

A firm is accustomed to training operators who do certain tasks on a production line. Those operators who attend the training co

Alexus [3.1K]

Answer:

Probability = 0.58

Step-by-step explanation:

This problem is solve by using Baye's Probability.

Let P(A) = Probability that operator attended training course = 50% = 0.5

P(B) = Probability that operator not attended training course = 50% = 0.5

Also P(Q) = Probability that operator meet their production quotas

Then, P(Q|A) = 90% = 0.9

P(Q|B) = 65% = 0.65

P(A|Q) = ?

Then by Baye's Theorem,

$P(A|Q) = \dfrac{P(Q|A) \times P(A)}{P(Q|A) \times P(A)+P(Q|B) \times P(B)}$

⇒ $P(A|Q) = \dfrac{0.9 \times\0.5 }{0.9 \times\0.5+0.65 \times\0.5}$

⇒ P(A|Q) = 0.58

which is required probability.

5 0

3 years ago

Anna earned 22 points on her last test. If there were 40 possible points, what was her percent grade?

dimulka [17.4K]

Answer:

55%

Step-by-step explanation:

Since Anna earned 22 points, and there was a total of 40 points, this means that she scored 22 out of 40 points. You can simplify this by dividing the denominator and numerator by 2. Then, you can multiply both the numerator and denominator by 5 to get a number out of 100.

$\frac{22}{40} = \frac{11}{20}=\frac{55}{100}*100%=55%$

6 0

3 years ago

your total savings varies inversely with the amount spent on Bill's. if your savings is $300 when your cost of Bill's are $65. W

tatyana61 [14]

Let S and B be savings and bills respectively. Then,
S α 1/B
S = k/B Where k = Constant.
When S = $300, B = 65

Then,
300 = k/65
k = 300*65 = 19500

Therefore,
For B = $145,

S= 19500/145 = $134.48

6 0

4 years ago

What is the solution to the equation 13.7y = 6.2y + 30?

il63 [147K]

Here, we are required to determine the solution to the equation: 13.7y = 6.2y + 30?

The solution to the equation is y = 7.5

The solution is thus,

13.7y = 6.2y + 30
13.7y - 6.2y = 30
7.5y = 30

Therefore, y = 30/7.5 = 4

Therefore, y = 4 is the solution to the equation.

Read more:

brainly.com/question/12184348

8 0

3 years ago

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

7 0

3 years ago