Answer:
A.0.4477
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected exam will require between 14 and 19 minutes to grade?
This probability is the pvalue of Z when X = 19 subtracted by the pvalue of Z when X = 14. So
X = 19



has a pvalue of 0.7389.
X = 14



has a pvalue of 0.2912
0.7389 - 0.2912 = 0.4477
So the correct answer is:
A.0.4477
Answer:
x^2-2x-13
Step-by-step explanation:
f(x) = 2x-5
g(x) = x^2 -4x-8
f(x) +g(x) = 2x-5 + x^2 -4x-8
Combine like terms
= x^2+2x-4x-5-8
=x^2-2x-13
Answer: 16x² + 8x + 1
Step-by-step explanation:
(4x + 1)(4x + 1)
This expansion can be done in two ways either by direct expansion or by indirect expansion
(1) Direct expansion
(4x + 1)(4x + 1 )
4x X 4x + 4x X 1 + 1 X 4x + 1 X 1
= 16x² + 4x + 4x + 1
= 16x² + 8x + 1
(2) Method
This can be written thus:
(4x + 1 )(4x + 1 ) = (4x + 1 )²
= (4x)² + 2( 4x X 1 ) + 1²
= 16x² + 2(4x) + 1
= 16x² + 8x + 1.
Answer:
102.3
Step-by-step explanation:
a_38 = -5
difference d= -2.9
We use general formula

WE make the formula for a_38 th term
Plug in 38 for n

Now plug in -2.9 for d and -5 for a_38


Now add 107.3 on both sides
102.3 = a_1
option A is correct