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3 years ago

BRUH HELP

Mathematics

1 answer:

TEA [102]3 years ago

4 0

Answer:

(E) 9

Step-by-step explanation:

I found what numbers worked in all three cases. I found that when a = 4 b = 5 c = 0, all of the equations were satisfied.

Equation 1 4 + 5 = 9

Equation 2 4 + 0 = 4

Equation 3 5 + 0 = 5

Also, a + b+ c or 4 + 5 + 0 = 9

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SOLVE EQUATION BY TAKING SQUARE ROOTS.<br> -100+81a^2=0

IceJOKER [234]

Answer:

a = ±10/9

Step-by-step explanation:

$-100+81a^2=0\\81a^2=100\\a^2=\frac{100}{81}\\\sqrt{a^2}=\sqrt{\frac{100}{81} }\\a=10/9\\a=-10/9$

7 0

3 years ago

Read 2 more answers

Ramer and knox began a partnership by investing $64,000 and $94,000, respectively. the partners agreed to share net income and l

Butoxors [25]

Each partner's share given a first-year net income of $102,800 is $-3,300.

Each partner's share given a first-year net loss of $20,800 is $-44,300.

<h3>What is each partner's share?</h3>

Partner' share = net income / loss - interest - salary salary allowance

Interest = ($64000 x 10%) + ($94000x 10%) = $15,800

Salary = $52,000 + $41,600 = $93,600

Share of net income = [$102,800 - (15,800 + 93600)] / 2 = $-3,300

Share of net loss = [-20,800 - (15,800 + 93600)] / 2 = $-44,300

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5 0

2 years ago

What is the solution to the following system of equations?

Semmy [17]

Answer:

(3,2)

Step-by-step explanation:

The system is

x + y = 5

x -y = 1

Add the equations to eliminate y

2x = 6----->x=3

Substitute this value in any equation

3+y = 5----->y=2

The solution is (3,2)

3 0

3 years ago

One pound of grapes costs $1.55. Which equation correctly shows a pair of equivalent ratios that can be used to find the cost of

stira [4]

Answer:

StartFraction 1.55 over 1 EndFraction = StartFraction x over 3.5 EndFraction

Step-by-step explanation:

$\frac{1.55}{1} = \frac{x}{3.5} \\ \\ \therefore \: x = 1.55 \times 3.5 \\ \\ \therefore \: x = \$ 5.425 \\ \\\therefore \: x\approx \$5.43$

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2 years ago

Read 2 more answers

Factor each expression.<br><br> Problem: 2p^3 + 6p^2 + 3p + 9<br> Answer: (p + 3) (2p2 + 3)

oee [108]

Factor by grouping
$2p^3 + 6p^2 + 3p + 9$
$2 p^3+6 p^2+3 p+9=\left(2 p^3+6 p^2\right)+(3 p+9)=\left(2 p^2\right) (p+3)+3 (p+3)$
$2 p^2 (p+3)+3 (p+3)$
$(p+3) \left(2 p^2+3\right)$

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3 years ago