3 years ago

Solve the system of two equations 2y=8 and 15y=2x-4

1 answer:

3 0

2y=8 can be simplified to y=4.

15(4)=2x-4
60=2x-4
64=2x
32=x

x=32, y=4
your solution is (32, 4)

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Naddika [18.5K]

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

$x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6$

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.

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