Answer:
76
2 real solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Standard Form: ax² + bx + c = 0
Discriminant: b² - 4ac
- Positive - 2 solutions
- Equal to 0 - 1 solution
- Negative - No solutions/Imaginary
Step-by-step explanation:
<u>Step 1: Define</u>
x² - 6x - 10 = 0
<u>Step 2: Identify Variables</u>
<em>Compare quadratic.</em>
x² - 6x - 10 = 0 ↔ ax² + bx + c = 0
a = 1, b = -6, c = -10
<u>Step 3: Find Discriminant</u>
- Substitute in variables [Discriminant]: (-6)² - 4(1)(-10)
- [Discriminant] Evaluate exponents: 36 - 4(1)(-10)
- [Discriminant] Multiply: 36 + 40
- [Discriminant] Add: 76
This tells us that our quadratic has 2 real solutions.
Answer:
what do you mean by 'm' ?
Step-by-step explanation:
Answer:
(a) SSS
.........................
She planted 7 zucchini, 14 cucumbers, and 22 tomatoes.
Let z = the number of zucchini planted. Since she planted twice as many cucumbers as zucchini, 2z is the number of cucumbers. She planted 8 more tomatoes than cucumbers, so 2z + 8 is the number of tomatoes. This gives us the equation
z + 2z + 2z + 8 = 43
Combining like terms, we have
5z + 8 = 43
Subtract 8 from each side:
5z + 8 - 8 = 43 - 8
5z = 35
Divide both sides by 5:
5z/5 = 35/5
z = 7
There were 7 zuccchini; 2*7 = 14 cucumbers; and 14+8=22 tomatoes.
