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3 years ago

Simplify: 36.6 ÷ (12)

Mathematics

1 answer:

Svetllana [295]3 years ago

4 0

Answer:

Hi! The answer to your question is $3.05$

Step-by-step explanation:

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☆Brainliest is greatly appreciated!☆

Hope this helps!!

- Brooklynn Deka

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How many multiples of $6$ are between $100$ and $500$?

lapo4ka [179]

ANSWER

EXPLANATION

This will form a sequence with first term:

$a_{1} = 102$

with constant difference d=6 and last term

$l = 486$

The last term is a term in the sequence, therefore;

$l=a_1+d(n-1)$

$486=102+6(n-1)$

$486 - 102 = 6(n-1)$

Simplify the LHS

$384= 6(n-1)$

Divide both sides by 6.

$64=n-1$

$64 + 1 = n$

Therefore

$n = 65$

Hence there are 65 multiples of 6.

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Answer:

1445

Step-by-step explanation:

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x = 55°

Step-by-step explanation:

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Y = mx+b that’ll help you answer it

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3 years ago

How many terms are there in a geometric series if the first term is 4, the common ration is 3 and the sum of the series is 160

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$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
S_n=160
\end{cases}$

$\bf 160=4\left( \cfrac{1-3^n}{1-3} \right)\implies 160=4\left( \cfrac{1-3^n}{-2} \right)\implies 160=-2(1-3^n)
\\\\\\
160=2(3^n-1)\implies \cfrac{160}{2}=3^n-1\implies 80=3^n-1
\\\\\\
81=3^n~~
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^4=3^n\implies 4=n$

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3 years ago