<span>along with units digit being < tens digit....let see if we can come up with something. ones unit must be 0,2,4,6,or 8. if 0 then tens unit can be 1-9 case1 if 2 then tens unit can be 3-9 case2 if 4 then tens unit can be 5-9 case3 if 6 then tens unit can be 7-9 case4 if 8 then tens unit can be 9 case5 : 108 is covered in case1 because 0<8 :</span><span>case5: 98----9+8=17 to be divisible by 9 hunderds unit has to be 1 and 198 is not divisible by 12 : case4:96,86,76...96---9+6=16 to be div by 9 100's unit has to be 3 and that is more than 200. 86 ...8+6=14 to be div by 9 100's unit has to be 4....to big same problem with 76 : case3:94,84,74,64,54...9+4, 8+4,7+4,6+4,5+4 all present problems with #'s larger than 200 : case2:92,82,72,62,52,42,32 ...92,82,and 72 all get throw out because #'s larger than 200. 62 is 6+2=8..to be divisble by 9 100's unit must be 1...162..not divisible by 12 take 52,42,32 end up with being over 200 : case1:90,80,70,60,50,40,30,20,10... 90 larger than 200...80 is 8+0=8 in order to be divisible by 9 100's unit has to be 1. 180.......guess what this number is divisible by 9 and 12 and is less than 200 applying divisibility rules for the rest of the numbers in this case make all the numbers to large >200 : SO WE HAVE GONE THROUGH ALL THE CASES AND 180 is the only one that qualified there could be a simpler way but I will have to think on that</span>lets work backwards
For example, the years 1600, 2000, and 2400 are century leap years since those numbers are divisible by 400, while 1700, 1800, 1900, 2100, 2200, and 2300 are common years despite being divisible by 4.
Ok let’s start off easy, the x and y stand for the missing number once you find those missing numbers you chose if the problems both used a same number if so it’s equivalent.if you had to use different numbers to get the answer it would be inconsistent and if you used even numbers to get the even answer than it would be consistent.i hoped that helped!
