Answer:
Step-by-step explanation:
Answer:
1 st expression is used in this
Answer:
Step-by-step explanation:
That '5' in f(5x) will compress the graph of x^2 horizontally.
If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.
Suppose you graphed f(x) = x^2 on the interval [-4, 4].
Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5]. In other words, the graph would be on a shorter interval, one shorter by a factor of 5.
Subtract the y then add the 4 to the other side so y=0
Step-by-step explanation:
x in (-oo:+oo)
1/7-(3*((3/7)*x-(2/7))) = 0
1/7-3*((3/7)*x-2/7) = 0
1/7-3*(3/7*x-2/7) = 0
(-3*7*(3/7*x-2/7))/7+1/7 = 0
1-3*7*(3/7*x-2/7) = 0
7-9*x = 0
(7-9*x)/7 = 0
(7-9*x)/7 = 0 // * 7
7-9*x = 0
7-9*x = 0 // - 7
-9*x = -7 // : -9
x = -7/(-9)
x = 7/9
x = 7/9
