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horsena [70]
3 years ago
11

Find the product of (3x-4)(2x^2+2x-1)

Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

6x^3  - 2x^2  -11x +4

Step-by-step explanation:

(3x-4)(2x^2+2x-1)

Multiply 3x  by the second term

3x* (2x^2+2x-1)

 6x^3  +6x^2 -3x


Multiply -4  by the second term

-4*(2x^2+2x-1)

 -8x^2 -8x+4


Add these together,  lining up the terms

 6x^3  +6x^2 -3x  

            -8x^2 -8x+4

----------------------------------

6x^3  - 2x^2  -11x +4

allsm [11]3 years ago
7 0

See picture for a reply to your question.




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Caroline, Colin & Sarah share some money.
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Answer:

2/9

Step-by-step explanation:

After Caroline's share,

1 - 1/9 = 8/9 is left

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1/(1+3) of 8/9

1/4 × 8/9

2/9

3 0
3 years ago
11x7/8 pls helpp i am so close from my test being over ty
Feliz [49]

Answer:

Exact Form:

77 /8

Decimal Form:

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Mixed Number Form:

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Step-by-step explanation:

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3 years ago
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John is twice as old as Fred. Four years ago John was 6 times as old. How old is John?
kari74 [83]

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3 years ago
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At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the
Over [174]

Answer:

c. 130

Step-by-step explanation:

Let call B the quantity of voters who voted yes for both propositions.

From the question we know that twice as many voters voted "yes" for R as for S, that can be written as the following equation:

R+B=2(S+B)

Where R is the number who voted "yes" for R but "no2 for S and S is the number who voted "yes" for S but "no" for R.

Replacing R by 750 and S by 310 and solving for B, we get:

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750+B=620+2B

2B-B=750-620

B=130

So, 130 voters voted yes for both propositions

7 0
3 years ago
F(x) = 2(x+1)3 even or odd
Andrews [41]

Answer:

Neither even  nor odd.

Step-by-step explanation:

f(x) =  2(x + 1)^3 = 2x^3 + 18x^2 + 54x + 54

f(-x) =  -2x^3 + 18x^2 - 54x + 54

If it was even f(x) would be = f(-x)   so it is NOT EVEN.

-f(x) =  2x^3 - 18x^2 + 54x - 54

So f(-x) is not = -f(x) so it is not ODD either.

7 0
3 years ago
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