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notsponge [240]
3 years ago
14

Write an equation for the graph of each line.​

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
7 0

Answer:

5. y = 2x + 4

6. y = -0.5x - 2

Step-by-step explanation:

5. Slope: (4-0)/(0--2) = 4/2 = 2

y-intercept: 4

y = 2x + 4

6. slope: (-2-0)/(0--4) = -2/4 = -0.5

y-intercept: -2

y = -0.5x - 2

emmasim [6.3K]3 years ago
3 0

Answer:

5. y = 2x + 4

6. y = (-1/2)x - 2

Step-by-step explanation:

5. We want to find the slope-intercept form of this, which is y = mx + b, where m is the slope and b is the y-intercept.

Slope is change in y divided by change in x. Here, let's take two random points: (-2, 0) and (0, 4). Then we have:

m = (4 - 0) / (0 - (-2)) = 4 / 2 = 2

The slope is thus 2.

The y-intercept is where the line crosses the y-axis. We see it does so at the point (0, 4), so b = 4.

Our equation is thus: y = 2x + 4.

6. Again, let's find the slope. Pick any two points: (-4, 0) and (0, -2). The slope will be:

m = (-2 - 0) / (0 - (-4)) = -2 / 4 = -1/2

Now, look at the point (0, -2); that's where the line crosses the y-axis, so the y-intercept is b = -2.

Thus, the equation is: y = (-1/2)x - 2.

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Answer:

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Step-by-step explanation:

9x13=117

117+7=124

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3 years ago
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What is the factorization of the expression below?
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

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3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
Katena32 [7]
Let's move like a crab, backwards some.

after 2 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2

after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
PLEASE PLEASE HELP ME IM STRUGGLING !!!
NARA [144]

Answer:

18 own 72 rent and its 80 perecnt

Step-by-step explanation:

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5 0
3 years ago
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I need the function for the volume of the box for number 1
rjkz [21]

Answer:

Step-by-step explanation:

The volume of a rectanguiar shape like this one is V = L * W * H, where the letters represent Length, Width and Height.  Here L is the longest dimension and is 28 - 2x; W is the width and is 22-2x; and finally, x is the height.  Thus, the volume of this box must be

V(x) = (28 - 2x)*(22 - 2x)*x

and we want to maximize V(x).  

One way of doing that is to graph V(x) and look for any local maximum of the graph.  We'd want to determine the value of x for which V(x) is a maximum.

Another way, for those who know some calculus, is to use the first and second derivatives to identify the value of  x at which V is at a maximum.

I have provided the function that you requested.  If you'd like for us to go all the way to a solution, please repost your question.

3 0
2 years ago
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