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ollegr [7]
3 years ago
5

A package of paper weighs 3\frac{4}{6} ounces. If Edward put 3\frac{1}{2} packages of paper on a scale, how much would they weig

h?
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

They would weight 1\frac{1}{21} ounces

Step-by-step explanation:

Weight of complete package of paper = 3 \frac{4}{6} ounces

Weight of complete package of paper =\frac{22}{6}ounces

Edward put3\frac{1}{2} packages of paper on a scale

So, Weight of 3\frac{1}{2} packages   = \frac{\frac{22}{6}}{3\frac{1}{2}}

Weight of 3\frac{1}{2} packages = \frac{\frac{22}{6}}{\frac{7}{2}}

Weight of 3\frac{1}{2} packages =\frac{22}{21}=1\frac{1}{21}

Hence They would weight 1\frac{1}{21} ounces

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lora16 [44]
56.5ft x 17ft x 1ft = 960.5ft^3.

The question wants the answer in ft^3. One of the measurements is given as 13 inches but that converts to 1ft. And with the volume formula for rectangles is widthxlenghtxheight. Plug in the numbers.
7 0
3 years ago
2) 45+ 17 = 62<br><br> 3) X + 5/6 = 7/16<br><br> 4) Y + 1/7 = 5/8
Montano1993 [528]

9514 1404 393

Answer:

  2) true

  3) X = -19/48

  4) Y = 27/56

Step-by-step explanation:

3) Subtract 5/6 from both sides

  X = 7/16 -5/6 = (7·6 -16·5)/(16·6) = (42 -80)/96

  X = -19/48

__

4) Subtract 1/7 from both sides

  Y = 5/8 -1/7 = (5·7 -8·1)/(8·7)

  Y = 27/56

6 0
3 years ago
Which set of equations is enough information to prove that lines a and b are parallel lines cut by transversal f? m∠4 = 110° and
atroni [7]

see the attached figure to better understand the problem

we know that

If a and b are parallel lines

then

m∠1=m∠4 --------> by alternate exterior angles

m∠3+m∠4=180\° --------> by supplementary angles

so

m∠3+m∠1=180\°

therefore

<u>the answer is the option</u>

m∠1 = 110° and m∠3 = 70°



4 0
3 years ago
Read 2 more answers
If CE bisects ZBCD and if m ZBCE = 3x - 6
horrorfan [7]

Answer:

m∠BCD = 90°

∠BCD is a right angle

Step-by-step explanation:

<em>If a ray bisects an angle, that means it divides the angle into two equal parts in measure</em>

∵ Ray CE bisects ∠BCD

→ Means divide it into two angles BCE and ECD which equal in measures

∴ m∠BCE = m∠ECD = \frac{1}{2} m∠BCD

∵ m∠BCE = 3x - 6

∵ m∠ECD = 2x + 11

→ Equate them to find x

∴ 3x - 6 = 2x + 11

→ Add 6 to both sides

∵ 3x - 6 + 6 = 2x + 11 + 6

∴ 3x = 2x + 17

→ Subtract 2x from both sides

∵ 3x - 2x = 2x - 2x + 17

∴ x = 17

∵ m∠BCE =  \frac{1}{2} m∠BCD

→ Substitute x in the measure of ∠BCE to find it, then use it to

   find m∠BCD

∵ m∠BCE = 3(17) - 6 = 51 - 6

∴  m∠BCE = 45°

∵ 45 = \frac{1}{2} m∠BCD

→ Multiply both sides by 2

∴ 90 = m∠BCD

∴ m∠BCD = 90°

→ The measure of the acute angle is less than 90°, the measure of

   the obtuse angle is greater than 90°, and the measure of the

   right angle is 90°

∴ ∠BCD is a right angle

6 0
3 years ago
Pittsburgh international airport had approximately 714,587 passengers in August 2009. write a number that is greater than 714,58
Pepsi [2]
A number than is greater than 714,587 is 238,646,454,476
8 0
3 years ago
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