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3 years ago

Find the area of the shaded

Mathematics

1 answer:

olga_2 [115]3 years ago

7 0

Answer:

31.4 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =6 inches

Central Angle of the sector =100°

$\text{Area of the sector=}\dfrac{\theta}{360^\circ}X\pi r^2$

$=\dfrac{100^\circ}{360^\circ}X\pi*6^2\\\\=10\pi\\\\=31.4$ Square Inches (correct to the nearest tenth of a square inch.)$

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Here is my question please answer and give a good explanation: Which expression cannot be used to calculate the total amount pai

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3 years ago

7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and<br> A = {6, 10, 14}, what is A'?

Tresset [83]

The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

Learn more about sets here:

brainly.com/question/2166579

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1 year ago

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ANEK [815]

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2 years ago

Read 2 more answers

If f(x)=(3+x)/(x-3), what is f(a+2)?

tigry1 [53]

Answer:

To answer items such as this, we directly substitute the a + 2 to the all the x's in the function such that,

f(a + 2) = (3 + a + 2) / (a + 2 - 3)

Simplifying the function generated above,

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2 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

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2 years ago