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2 years ago

Which is an incorrect rounding for 53.864A.54B.53.87C.53.9D.50

Mathematics

1 answer:

kotegsom [21]2 years ago

7 0

The incorrect rounding for 53.864 is 53.87

<h3>How to approximation a decimal?</h3>

The decimal to be approximated is as follows;

53.864

The first option rounded the decimal to 2 significant figures or a whole number.

The second option is incorrect because they rounded it wrongly to 2 decimal places. The correct 2 decimal round is 53.86.

The third option is approximated rightly to one decimal place.

The last option is rounded to the closes tens term.

learn more on approximation here: brainly.com/question/9608644

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2 is 4% of what number?

kaheart [24]

$x-searched\ number\\\\4\%x=2\\\\0.04x=2\ \ \ \ |:0.04\\\\x=50\\\\2\ is\ 4\%\ of\ 50$

6 0

3 years ago

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

7 0

3 years ago

Line 2 shows position data for an object that is speeding up. Use the centimeter ruler to measure the distance of each dot from

monitta

Answer:

1= 0

2= 0.5

3= 1.5

4= 3

5= 5

6= 7.5

7= 10.5

8= 14

explanation: This is the edmentum answer

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3 years ago

To find the height of the peak, list the corresponding sides and angles of the two triangles you and Tyler have created. (6 poin

sukhopar [10]

We know that

Right triangles PBM and MTF are similar
because
angle PMB=angle TMF
and
angle BPM=angle FTM
and
angle B =angle F=90 degrees
so
corresponding sides are
BM and MF
PB and TF
PM and MT
(PB/TF)=BM/MF
solve for PB
PB=(TF*BM)/MF
where
TF=6ft
BM=20 ft
MF=3 ft
so
PB=(6*20)/3------> 40 ft

the answer is
<span>the height of the peak is 40 ft</span>

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3 years ago

You spent 1/5 of your birthday money on 2 video games. If each video game cost the same amount, what fraction of your birthday m

Elza [17]

Answer:

1/10

Step-by-step explanation:

Let total money be m

Then, the money spent on 2 video games is 1/5m

<u>Each game costs:</u>

1/5m ÷ 2 =
1/10m

So each video game costs 1/10 of birthday money

4 0

3 years ago

Read 2 more answers