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astra-53 [7]
4 years ago
8

There are several marbles in a bag: two red, four green, one blue, and five yellow. What is the probability of randomly drawing

a green marble, replacing it, and then randomly drawing a yellow marble?
Mathematics
1 answer:
GREYUIT [131]4 years ago
5 0

Answer:

The probability is 5/36

Step-by-step explanation:

The total number of marbles is 2 + 4 + 1 + 5 = 12 marbles

The probability of randomly drawing a green marble would be

number of green marble/total number of marbles = 4/12 = 1/3

Now since we are replacing the total number of marbles stays the same

so, the probability of drawing a yellow marble now will be ;

number of yellow marbles/total number of marbles = 5/12

So the total probability we are having here would be; 1/3 * 5/12 = 5/36

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Answer:

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Step-by-step explanation:

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Third month: 66.50                   I        Third month: 109.00

Fourth month: 82.00                I         Fourth month: 116.00

Fifth month: 97.50                    I         Fifth month: 123.00

Sixth month: 113.00                  I        Sixth month: 130.00

Seventh month: 128.50           I        Seventh month: 137.00

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Find volume of cone z=sqrt(x^2+y^2) that is bounded with z=5 and z=7
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Convert to cylindrical coordinates first, using

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}

Then the volume is

\displaystyle\int_{\zeta=5}^{\zeta=7}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\zeta}r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta
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=\dfrac{218\pi}3
5 0
3 years ago
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